X^2+25x+10=150

Solution for X^2+25x+10=150 equation:

X^2+25X+10=150

We move all terms to the left:

X^2+25X+10-(150)=0

We add all the numbers together, and all the variables

X^2+25X-140=0

a = 1; b = 25; c = -140;
Δ = b2-4ac
Δ = 252-4·1·(-140)
Δ = 1185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{1185}}{2*1}=\frac{-25-\sqrt{1185}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{1185}}{2*1}=\frac{-25+\sqrt{1185}}{2}
$